Probability
See also: numbers, Permutations and Combinations
Conditional Probability
For two events A and B, the conditional probability of A, is the probability of A given the occurence (or non-occurence) of the B.
The conditional probability of A given B is defined by
| P(A | B) = | P(A ∩ B) |
| P(B) |
If events A and B are independent, P(A ∩ B) = P(A)P( B). Hence
- P(A | B) = P(A)
- P(B | A) = P(B)
If events A and B are mutually exclusive, P(A ∩ B) = 0. Hence, if P(B) > 0, then P(A | B) = 0.
Example:
In a certain region, on any day of the year, the probability that it's cloudy is 0.4. It's also known that there's a 0.3 probability that any day is a cloudy and rainy day. Given that today is cloudy, what is the probability that it will rain?
Let C be the event that it's cloudy and R be the event that it rains.
P(C) = 0.4
P(R ∩ C) = 0.3
| P(R | C) = | P(R ∩ C) |
| P(C) | |
| = | 0.3 |
| 0.4 | |
| = | 0.75 |
Another example:
In a city, the ratio between men and women is 6:4. Thirty percent of the men are vegetarian. What percentage of the city residents are vegetarian men?
Let M be the probability of any random resident being a man and V be the probability that any random resident being a vegetarian.
P(M) = 0.6
P(V | M) = 0.3
| P(V | M) = | P(V ∩ M) |
| P(M) | |
| 0.3 = | P(V ∩ M) |
| 0.6 | |
| P(V ∩ M) = | 0.3 × 0.6 |
| P(V ∩ M) = | 0.18 |
Eighteen percent of the city residents are vegetarian men.
| Previous: Independent and Mutually exclusive events |
Next: Bayes' Theorem |
See also: numbers, Permutations and Combinations

